document.write( "Question 437577: Flying against a headwind, a plane covers 900 miles in 2 hours. The return trip with a tailwind only takes an hour and a half. Find the speed of the wind, and the speed of the plane within the air mass. \n" ); document.write( "

Algebra.Com's Answer #302707 by mananth(16946) $\"\"$ $\"About$

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against wind 2.00 hours
\n" ); document.write( "with wind 1.50 hours
\n" ); document.write( "
\n" ); document.write( "Distance = same=900
\n" ); document.write( "plane speed =x
\n" ); document.write( "wind speed =y
\n" ); document.write( "t=d/r
\n" ); document.write( "900/(x-y)=2.00
\n" ); document.write( "2(x-y)= 900.00
\n" ); document.write( "2x-2y=900 ....................1
\n" ); document.write( "900/(x+y)=1.50
\n" ); document.write( "1.50(x+ y)=900
\n" ); document.write( "1.50x+1.50y=900 ...............2
\n" ); document.write( "Multiply (1) by 1.50
\n" ); document.write( "Multiply (2) by 2.00
\n" ); document.write( "we get
\n" ); document.write( "3x-3y=1350
\n" ); document.write( "3x+3y=1800
\n" ); document.write( "6x=3150
\n" ); document.write( "/6
\n" ); document.write( "x=525mph plane speed
\n" ); document.write( "
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "2x-2y=900
\n" ); document.write( "1050-2y =900
\n" ); document.write( "-2y=900-1050
\n" ); document.write( "-2y=-150
\n" ); document.write( "y=75 mph wind speed
\n" ); document.write( " \n" ); document.write( "

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