document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=437496>Question 437496</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In 4 years, Mike will be 3 times as old as Chris will be. The sum of their ages now is 56.                                                                      I just need to know how to set this equation up! Is there a method for all problems like this? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #302640 by </B><A HREF=/tutors/aboutme.mpl?userid=rwm><B>rwm(914)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rwm><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=302640\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (m+4)=3*(c+4)<BR>\n" );
document.write( "m+c=56<BR>\n" );
document.write( "c=12 m=44<BR>\n" );
document.write( "in 4 years<BR>\n" );
document.write( "check<BR>\n" );
document.write( "44+4=48=3*(12+4)=3*16=48\r<BR>\n" );
document.write( "\n" );
document.write( "ok<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );