document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=437288>Question 437288</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The gravitational force F between two objects is inversely proportional to the square of the distance between the objects. If the force F is 1.62x 10^-6N when the objects are 25cm apart, what is the gravitational force when the objects are 35cm apart? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #302562 by </B><A HREF=/tutors/aboutme.mpl?userid=Gogonati><B>Gogonati(855)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Gogonati><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Gogonati><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=302562\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since the distance differ 35-25=10 cm and the F is inversely proportional to the square of the distance the F will decrease by <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10%5E2 ALIGN=MIDDLE  ALT=\"10%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > or 100, therefore we divide the F by 100 and find the new gravitational force:\r<BR>\n" );
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document.write( "  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=F%5B2%5D=%281.62%2A10%5E-6%29%2F10%5E2=%281.62%2A10%5E-8%29 ALIGN=MIDDLE  ALT=\"F%5B2%5D=%281.62%2A10%5E-6%29%2F10%5E2=%281.62%2A10%5E-8%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >N.\r<BR>\n" );
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