document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=437278>Question 437278</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The lens of a camerahas a focal length (F) that satisfies the equation. \r<BR>\n" );
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document.write( "F= do x dk/(do + dk) \r<BR>\n" );
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document.write( "where do is the distance from the object to the lens and dk is the distance from the lens to the film.  \r<BR>\n" );
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document.write( "If an object is 60 cm from the cam lens and the lens is 10 cm from the film, what is the approximate focal length in centimeters of the lens?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #302558 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=302558\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> F=do x dk/(do+dk)<BR>\n" );
document.write( "\"=60 x 10/60+10<BR>\n" );
document.write( "\"=60 x 10/70<BR>\n" );
document.write( "\"=60/7 cm.. </SPAN>\n" );
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