document.write( "Question 437181: Here's the question: \"A motorcycle travels 40 miles in the same time that a bicycle travels 15 miles. If the bike travels 20 miles per hour slower than the motorcycle, find the speed of the bike\"\r
\n" ); document.write( "\n" ); document.write( "I've tried setting it up with this equation:
\n" ); document.write( "40+15=x-20
\n" ); document.write( "then solved.
\n" ); document.write( "55=x-20
\n" ); document.write( "35=x\r
\n" ); document.write( "\n" ); document.write( "I'm just not entirely sure that I have the equation set up right.
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Algebra.Com's Answer #302449 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!

 
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document.write( "Hi
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document.write( "bike travels 20 miles per hour slower 
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document.write( "Let x and (x -20mph) represent speed of the motorcycle and bike reapectively
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document.write( "Question states*** NOte: D/r = t, Times same for both 
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document.write( " 40m/(x) = 15m/(x-20)   Cross Multiplying 
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document.write( "   15x = 40(x-20)
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document.write( "  800 = 25x
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document.write( "      x = 32mph, speed of motorcycle.  Speed of the Bike 12mph   (32mph-20mph) \r
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document.write( " CHECKING our Answer***
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document.write( "  40m/32mph = 15m/12mph = 1.25hr or 48min \n" );
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