document.write( "Question 437257: Make a graph of y=-x^2-2x+3 and find the vertex, y-intercept, extra points.
\n" );
document.write( "I don't understand how I can find the vertex, y-intercept and extra points.
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #302441 by Gogonati(855)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "\n" ); document.write( "This graph represent a parabola: \n" ); document.write( "\n" ); document.write( "From the final expression we see that the vertex is: (-1, 4)\r \n" ); document.write( "\n" ); document.write( "To find the y-intercept we make x=0: y=-0^2-2*0+3=3; (0, 3)\r \n" ); document.write( "\n" ); document.write( "Other extra points are the x-intercepts: -x^2-2x+3=(x+3)(x-1)=0: x=-3 and x=1;\r \n" ); document.write( "\n" ); document.write( "x-intercepts are:(-3, 0) and (1, 0).\r \n" ); document.write( "\n" ); document.write( "Done. \n" ); document.write( " |