document.write( "Question 437257: Make a graph of y=-x^2-2x+3 and find the vertex, y-intercept, extra points.
\n" ); document.write( "I don't understand how I can find the vertex, y-intercept and extra points.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #302441 by Gogonati(855)\"\" \"About 
You can put this solution on YOUR website!
\"graph%28300%2C+300%2C+-5%2C+5%2C+-5%2C+5%2C+-x%5E2-2x%2B3%29\"\r
\n" ); document.write( "\n" ); document.write( "This graph represent a parabola: \"y=-x%5E2-2x%2B3=-%28x%5E2%2B2x%2B1%29%2B1%2B3=-%28x%2B1%29%5E2%2B4\"\r
\n" ); document.write( "\n" ); document.write( "From the final expression we see that the vertex is: (-1, 4)\r
\n" ); document.write( "\n" ); document.write( "To find the y-intercept we make x=0: y=-0^2-2*0+3=3; (0, 3)\r
\n" ); document.write( "\n" ); document.write( "Other extra points are the x-intercepts: -x^2-2x+3=(x+3)(x-1)=0: x=-3 and x=1;\r
\n" ); document.write( "\n" ); document.write( "x-intercepts are:(-3, 0) and (1, 0).\r
\n" ); document.write( "\n" ); document.write( "Done.
\n" ); document.write( "
\n" );