document.write( "Question 45520This question is from textbook College Algebra
\n" ); document.write( ": Use the property of Inverse Functions to show that f and g are inverses of each other:\r
\n" ); document.write( "\n" ); document.write( "f(x) = x^3 + 1; g(x) = (x-1)^(1/3)\r
\n" ); document.write( "\n" ); document.write( "f(g(x)) = f((x-1)^1/3) + 1 = x-1 + 1 = x
\n" ); document.write( "g(f(x)) = g(x^3 + 1) = (x^3 + 1)^3 + 1 = x + 1 -1 = x\r
\n" ); document.write( "\n" ); document.write( "f and g are inverses of each other.\r
\n" ); document.write( "\n" ); document.write( "Thank you very much!
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Algebra.Com's Answer #30243 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
f(x) = x^3 + 1; g(x) = (x-1)^(1/3)
\n" ); document.write( "f(g(x)) = f((x-1)^1/3)^3 + 1 = x-1 + 1 = x
\n" ); document.write( "g(f(x)=g(x^3 + 1) = [(x^3+1-1)^(1/3)]=[x^3]^(1/3) = x \r
\n" ); document.write( "\n" ); document.write( "Your conclusion is correct but I have adjusted your
\n" ); document.write( "posting.\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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