document.write( "Question 437159: How many lines with a slope of -1 are tangent to the circle x^2 + y^2 = 25 \n" ); document.write( "
Algebra.Com's Answer #302406 by lwsshak3(11628) ![]() You can put this solution on YOUR website! How many lines with a slope of -1 are tangent to the circle x^2 + y^2 = 25 \n" ); document.write( ".. \n" ); document.write( "x^2 + y^2 = 25 \n" ); document.write( "There would be two points where a line of -1 slope would be tangent to the circle. The (x,y) coordinates at the two points would be (5sqrt(2)/2,5sqrt(2)/2) and (-5sqrt(2)/2,-5sqrt(2)/2) \n" ); document.write( "Using the standard form for a straight line, y=mx+b, we have (x,y) coordinates of a point on each line. All we need is find b to complete the equation. \n" ); document.write( ".. \n" ); document.write( "For the first line: \n" ); document.write( "y=mx+b \n" ); document.write( "5sqrt(2)/2=(-1)5sqrt(2)/2+b \n" ); document.write( "5sqrt(2)=b \n" ); document.write( "Equation of line: y=-x+5sqrt(2) \n" ); document.write( ".. \n" ); document.write( "For the second line: \n" ); document.write( "y=mx+b \n" ); document.write( "-5sqrt(2)/2=(-1)-5sqrt(2)/2+b \n" ); document.write( "-5sqrt(2)=b \n" ); document.write( "Equation of line: y=-x-5sqrt(2) \n" ); document.write( "see graph below: \n" ); document.write( ".. \n" ); document.write( "y=+-(25-x^2)^.5 \n" ); document.write( "y=-x+5*2^.5 \n" ); document.write( "y=-x-5*2^.5 \n" ); document.write( " \n" ); document.write( ".. \n" ); document.write( " |