document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=437217>Question 437217</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A farmer has 200 hectares of land suitable for cultivating crops A, B, and C. The<BR>\n" );
document.write( "cost of cultivating each crop is<BR>\n" );
document.write( "• $40 per hectare for crop A<BR>\n" );
document.write( "• $60 per hectare for crop B<BR>\n" );
document.write( "• $80 per hectare for crop C<BR>\n" );
document.write( "The labour hours required for each crop are<BR>\n" );
document.write( "• 20 labour hours per hectare for crop A<BR>\n" );
document.write( "• 25 labour hours per hectare for crop B<BR>\n" );
document.write( "• 40 labour hours per hectare for crop C.<BR>\n" );
document.write( "The farmer has 200 hectares of land, a budget of $12600, and a workforce that can<BR>\n" );
document.write( "work a total of 5950 labour hours. How many hectares of each crop should he plant<BR>\n" );
document.write( "to use up all his available land, budget, and labour hours?<BR>\n" );
document.write( "[Hint: land, budget and labour correspond to 3 linear equations] </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #302398 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=302398\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Crop A - x<BR>\n" );
document.write( "Crop B -y<BR>\n" );
document.write( "Crop C-z\r<BR>\n" );
document.write( "\n" );
document.write( "x+y+z=200.....................1<BR>\n" );
document.write( "40x+60y+80z= 12600.............2<BR>\n" );
document.write( "20x+25y+40z=5950...............3<BR>\n" );
document.write( "consider equation 1 &2	Eliminate y												<BR>\n" );
document.write( "Multiply 1 by	-60									<BR>\n" );
document.write( "Multiply 2 by	1									<BR>\n" );
document.write( "we get																<BR>\n" );
document.write( "-60x-60y-60z=-12000						<BR>\n" );
document.write( "40x+60y+80z=12600						<BR>\n" );
document.write( "Add the two 																<BR>\n" );
document.write( "-20x+20z=600	-------------4	<BR>\n" );
document.write( "consider equation 2 & 3	Eliminate z		<BR>\n" );
document.write( "Multiply 2 by -5<BR>\n" );
document.write( "multiply 3 by 12												<BR>\n" );
document.write( "we get 																<BR>\n" );
document.write( "-200x-300y-400	z=-63000							<BR>\n" );
document.write( "240x+300y+480z=	71400							<BR>\n" );
document.write( "Add the two 																<BR>\n" );
document.write( "40x+80z=8400	-------------5				5		<BR>\n" );
document.write( "Consider (4) & (5)			Eliminate z													<BR>\n" );
document.write( "Multiply 4 by	2												<BR>\n" );
document.write( "Multiply (5) by	1												<BR>\n" );
document.write( "we get															<BR>\n" );
document.write( "-40x+40z=1200										<BR>\n" );
document.write( "40x+80z=8400										<BR>\n" );
document.write( "Add the two 																<BR>\n" );
document.write( "120z=9600										<BR>\n" );
document.write( "/120															<BR>\n" );
document.write( "z=80									<BR>\n" );
document.write( "Plug the value of z in	5						<BR>\n" );
document.write( "40x+6400=8400								<BR>\n" );
document.write( "40x=2000<BR>\n" );
document.write( "								<BR>\n" );
document.write( "x=50														<BR>\n" );
document.write( "plug value of x & z in					1											<BR>\n" );
document.write( "50+y+80=200									<BR>\n" );
document.write( "y=-50-80+200									<BR>\n" );
document.write( "y=70														\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );