document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=437200>Question 437200</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is seven less than another number. The sum of the numbers<BR>\n" );
document.write( "is thirty-three. Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #302387 by </B><A HREF=/tutors/aboutme.mpl?userid=Adrish><B>Adrish(44)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Adrish><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=302387\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solutions: Let the numbers be \"x\" and \"y\"\r<BR>\n" );
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document.write( "Given:  x=y-7................(1)<BR>\n" );
document.write( "and     x+y=33...............(2)\r<BR>\n" );
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document.write( "substitute the value of x in equation(2) we get,\r<BR>\n" );
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document.write( "(y-7)+y=33<BR>\n" );
document.write( "2y-7=33<BR>\n" );
document.write( "2y=33+7<BR>\n" );
document.write( "2y=40<BR>\n" );
document.write( "y=40/2<BR>\n" );
document.write( "y=20\r<BR>\n" );
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document.write( "Substitute the value of y in equation(1) we get,\r<BR>\n" );
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document.write( "x=20-7<BR>\n" );
document.write( "x=13\r<BR>\n" );
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document.write( "Therefore the numbers are 13 and 20 </SPAN>\n" );
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