document.write( "Question 437160: A rectangular storage area is 8.0 meter longer than it is wide. If the area is 28m^2, what are its dimensions? \n" ); document.write( "
Algebra.Com's Answer #302373 by oberobic(2304)\"\" \"About 
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Area = Length * Width
\n" ); document.write( "A = L*W
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\n" ); document.write( "We're told
\n" ); document.write( "A = 28
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\n" ); document.write( "We're also told the length is 8 meters greater than width.
\n" ); document.write( "L = W+8
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\n" ); document.write( "L * W = A
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\n" ); document.write( "Substituting:
\n" ); document.write( "(W+8) * W = 28
\n" ); document.write( "W^2 + 8W = 28
\n" ); document.write( "Subtract 28 from both sides
\n" ); document.write( "W^2 + 8W - 28 = 0
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\n" ); document.write( "This does not factor easily, so use the quadratic equation.
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"aW%5E2%2BbW%2Bc=0\" (in our case \"1W%5E2%2B8W%2B-28+=+0\") has the following solutons:
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\n" ); document.write( " \"W%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%288%29%5E2-4%2A1%2A-28=176\".
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\n" ); document.write( " Discriminant d=176 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-8%2B-sqrt%28+176+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"W%5B1%5D+=+%28-%288%29%2Bsqrt%28+176+%29%29%2F2%5C1+=+2.6332495807108\"
\n" ); document.write( " \"W%5B2%5D+=+%28-%288%29-sqrt%28+176+%29%29%2F2%5C1+=+-10.6332495807108\"
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\n" ); document.write( " Quadratic expression \"1W%5E2%2B8W%2B-28\" can be factored:
\n" ); document.write( " \"1W%5E2%2B8W%2B-28+=+1%28W-2.6332495807108%29%2A%28W--10.6332495807108%29\"
\n" ); document.write( " Again, the answer is: 2.6332495807108, -10.6332495807108.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B8%2Ax%2B-28+%29\"

\n" ); document.write( "\n" ); document.write( ".
\n" ); document.write( "A negative value for W does not make sense, so we choose W = 2.633.
\n" ); document.write( "L = W + 8 = 10.633.
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\n" ); document.write( "Checking.
\n" ); document.write( "10.633*2.633=27.9966 or about 28.
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\n" ); document.write( "Done.
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