document.write( "Question 437083: Parking lot dimensions. A parking lot has a perimeter of 500ft. The width is 20ft less than the lenght. find the dimensions. \n" ); document.write( "

Algebra.Com's Answer #302367 by oberobic(2304) $\"\"$ $\"About$

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Assuming the parking lot is a rectangle, which is key, we know that:
\n" ); document.write( "Perimeter = 2*Length + 2*Width
\n" ); document.write( "P = 2L + 2W
\n" ); document.write( "P = 2(L+W)
\n" ); document.write( ".
\n" ); document.write( "We're told that
\n" ); document.write( "P = 500
\n" ); document.write( "So,
\n" ); document.write( "2(L+W) = 500
\n" ); document.write( "L+W = 250
\n" ); document.write( ".
\n" ); document.write( "And we're told:
\n" ); document.write( "L = W+20
\n" ); document.write( ".
\n" ); document.write( "Substituting, we have:
\n" ); document.write( "L+W = 250
\n" ); document.write( "(W+20) + W = 250
\n" ); document.write( "2W = 230
\n" ); document.write( "W = 115
\n" ); document.write( ".
\n" ); document.write( "So,
\n" ); document.write( "L = 250 -115
\n" ); document.write( "L = 135
\n" ); document.write( ".
\n" ); document.write( "The parking lot has dimensions: Length = 135 and Width = 115.
\n" ); document.write( ".
\n" ); document.write( "Done. \n" ); document.write( "

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