document.write( "Question 437112: James wishes to enclose a rectangular dog kennel with 150 feet of fencing. He would like the kennel to be twice as long as it is wide. What must be the kennel's dimension? \n" ); document.write( "

Algebra.Com's Answer #302365 by oberobic(2304) $\"\"$ $\"About$

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The fence will define the perimeter of the rectangle.
\n" ); document.write( "P = 2*width + 2*length
\n" ); document.write( "P = 150
\n" ); document.write( "We're told
\n" ); document.write( "l = 2w
\n" ); document.write( "150 = 2w + 2l
\n" ); document.write( "Substituting
\n" ); document.write( "150 = 2w + 2(2w)
\n" ); document.write( "150 = 2w + 4w
\n" ); document.write( "150 = 6w
\n" ); document.write( "6w = 150
\n" ); document.write( "w = 25
\n" ); document.write( "l = 2w
\n" ); document.write( "l = 50
\n" ); document.write( ".
\n" ); document.write( "Always check your answer!
\n" ); document.write( "2(25) + 2(50) = 150??
\n" ); document.write( "50 + 100 = 150
\n" ); document.write( "Checks.
\n" ); document.write( ".
\n" ); document.write( "Answer: The kennel's dimensions should be 50 feet long by 25 feet wide.
\n" ); document.write( ".
\n" ); document.write( "Done. \n" ); document.write( "

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