document.write( "Question 437124: Make a graph of y=6x^2-4x-3 and find the vertex, y-intercept, extra points.\r
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document.write( "I don't understand how I can find the vertex, y-intercept and extra points. \n" );
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Algebra.Com's Answer #302350 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Make a graph of y=6x^2-4x-3 and find the vertex, y-intercept, extra points. \n" ); document.write( "----------- \n" ); document.write( "For the y-intercept, set x = 0 \n" ); document.write( "--> y = -3, or (0,-3) \n" ); document.write( "---------------- \n" ); document.write( "For the vertex, find the line of symmetry \n" ); document.write( "It's x = -b/2a \n" ); document.write( "x = -(-4)/(2*6) = 1/3 \n" ); document.write( "The vertex is (1/3,f(1/3)) \n" ); document.write( "Sub 1/3 for x \n" ); document.write( "--> 6*(1/9) - 4/3 - 3 \n" ); document.write( "= - 11/3 \n" ); document.write( "Vertex at (1/3,-11/3) \n" ); document.write( "--------------- \n" ); document.write( "For \"extra points\", pick values for x and find y \n" ); document.write( "x = 1, y = -1 --> (1,-1) \n" ); document.write( "x = 2, y = 13 --> (2,13) etc \n" ); document.write( " \n" ); document.write( " |