document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=45304>Question 45304</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am not understanding the vertical and horizontal asympote of the rational function. Can someone please help me?\r<BR>\n" );
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document.write( "Find the vertical asympote of the rational function f(x)= 3x-12/4x-2\r<BR>\n" );
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document.write( "Find the horizontal asympote of the rational function f(x)= 8x-12/4x-2\r<BR>\n" );
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document.write( "Any help and explanation would be greatly apprecaited.\r<BR>\n" );
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document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #30235 by </B><A HREF=/tutors/aboutme.mpl?userid=jake_6233><B>jake_6233(74)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jake_6233><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=30235\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the vertical asympote of the rational function f(x)= 3x-12/4x-2 <BR>\n" );
document.write( "Find the horizontal asympote of the rational function f(x)= 8x-12/4x-2 <BR>\n" );
document.write( "by definition a vertical asymptote f(x) goes to infinity or negative infinity so the vetical asymptote is x =1/2 this is because if you plug x=1/2 into the denominator you will get 0<BR>\n" );
document.write( "By definition a horizontal asymptote is defined f(x)=b as x goes to positive or negative infinity so (8x-12)/(4x-2)  we have y=2 this is because as x gets very large or very small you will get closer and closer to 8/4 or 2 realixe that the -12 and -2 are constants that \"drop out\" a \"trick\" is to use the coeficcients of x as long as x has the same power in both the numerator and denominator<BR>\n" );
document.write( "Please let me know if this helps you </SPAN>\n" );
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