document.write( "Question 436971: The formula h=-16t^2+vt gives the height h in feet of an object after t seconds when it is shot upward into the air with a velocity v in feet per second. After how many seconds will an object hit the ground if it is shot upward with an initial velocity of 240 feet per second?
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Algebra.Com's Answer #302328 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The formula h=-16t^2+vt gives the height h in feet of an object after t seconds \n" ); document.write( " when it is shot upward into the air with a velocity v in feet per second. \n" ); document.write( " After how many seconds will an object hit the ground if it is shot upward with \n" ); document.write( " an initial velocity of 240 feet per second? \n" ); document.write( ": \n" ); document.write( "Replace h with 0 and v with 240, write the equation: \n" ); document.write( "-16t^2 + 240t = 0 \n" ); document.write( "Simplify and change the sign, divide by -8 \n" ); document.write( "2t^2 - 30t = 0 \n" ); document.write( "Factor \n" ); document.write( "t(2t - 30) = 0 \n" ); document.write( "Two solutions \n" ); document.write( "t = 0 (at ground level initially) \n" ); document.write( "and \n" ); document.write( "2t = 30 \n" ); document.write( "t = 15 sec to hit the ground \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this in the original equation \n" ); document.write( "-16(15^2) + 240(15) = \n" ); document.write( "-16(225) + 3600 = 0 \n" ); document.write( " |