document.write( "Question 436946: How do I solve this problem,\r
\n" ); document.write( "\n" ); document.write( "Write the slope-intercept form of an equation of the line that passes through the y-axis at 5 and is perpendicular to the graph of 2x=3y+4.
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Algebra.Com's Answer #302283 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Your line represented by \"y+=+mx%2Bb\"
\n" ); document.write( "the line that passes through the \"y-axis\" at \"5\"\r
\n" ); document.write( "\n" ); document.write( "it means if \"x=0\", \"y=5\"; and that means \"b=5\"\r
\n" ); document.write( "\n" ); document.write( " \"y+=+mx%2B5\"\r
\n" ); document.write( "\n" ); document.write( "To find the slope of this line perpendicular to \"2x=3y%2B4\", write it in sloe-intercept form first:\r
\n" ); document.write( "\n" ); document.write( "\"+2x=3y%2B4\"\r
\n" ); document.write( "\n" ); document.write( "\"+3y=2x-4\"\r
\n" ); document.write( "\n" ); document.write( "\"+y=%282%2F3%29x-4%2F3\"\r
\n" ); document.write( "\n" ); document.write( "the slope is 2/3, and you take the negative reciprocal of the slop of your given line, or -3/2\r
\n" ); document.write( "\n" ); document.write( "This gives you a general line of \"y+=+-%283%2F2%29x%2B5\". \r
\n" ); document.write( "\n" ); document.write( "now, graph them both:\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C+500%2C+-10%2C+10%2C+-10%2C+10%2C-%283%2F2%29x%2B5%2C+%282%2F3%29x-4%2F3%29+\"\r
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