document.write( "Question 45416: Find an equation of a line when it passes throught he points (4/3, -1/2) and
\n" ); document.write( "(-2/3, 4).
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Algebra.Com's Answer #30225 by jake_6233(74)\"\" \"About 
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Find an equation of a line when it passes throught he points (4/3, -1/2) and
\n" ); document.write( "(-2/3, 4).
\n" ); document.write( "An easy way to solve this problem is to find the slope y2-y1/x2-x1 These are subscripts not exponents 4- (-1/2)/(-2/3 -4/3) = (9/2)/(-2) = -9/4 =m
\n" ); document.write( "Then choosing one pair of coordinates solve the equation y-y1 =m(x-x1)
\n" ); document.write( "y - (-1/2) = -9/4(x-4/3)
\n" ); document.write( "y+1/2 = -9/4(x-4/3)
\n" ); document.write( "y= -9/4x + 36/12 -6/12\r
\n" ); document.write( "\n" ); document.write( "y= -9/4x -5/2 is the answer please let me know if you need any clarification
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