document.write( "Question 436850: Coordinate-system/436845\r
\n" );
document.write( "\n" );
document.write( "Let H(x)= 2x^3 + 5x - 2
\n" );
document.write( " Find H^(-1) (-2).
\n" );
document.write( "trying to understand your method of distribution\r
\n" );
document.write( "\n" );
document.write( "==>
\n" );
document.write( "==>
\n" );
document.write( "==> \n" );
document.write( "
Algebra.Com's Answer #302199 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Let H(x)= 2x^3 + 5x - 2 \n" ); document.write( "Find H^(-1) (-2). \n" ); document.write( "------------------ \n" ); document.write( "The exponent symbol ^ doesn't make sense there. \n" ); document.write( "If you want H(-1) and H(-2) \n" ); document.write( "Let H(x)= 2x^3 + 5x - 2 \n" ); document.write( "Find H(-1) \n" ); document.write( "Sub -1 for x \n" ); document.write( "H(-1) = 2(-1)^3 + 5(-1) - 2 = -2 -5 -2 \n" ); document.write( "H(-1) = -9 \n" ); document.write( "------------ \n" ); document.write( "H(-2) = 2(-2)^3 + 5(-2) - 2 = -16 -10 -2 \n" ); document.write( "H(-2) = -28 \n" ); document.write( " |