document.write( "Question 436796: Please help me find the eXACT solutions of the given equation, in radians, that lie in the interval [0, 2π).
\n" ); document.write( "6 cos3(x) + 6 cos(x) = 0 \r
\n" ); document.write( "\n" ); document.write( "I started it by factoring
\n" ); document.write( "6cos(x)*[cos2(x)+cos(x)]=0 \r
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Algebra.Com's Answer #302189 by robertb(5830)\"\" \"About 
You can put this solution on YOUR website!
\"6+cos3%28x%29+%2B+6+cos%28x%29+=+0\" ==> cos3x + cosx = 0\r
\n" ); document.write( "\n" ); document.write( "==> cos2x cosx - sin2x sinx + cosx = 0
\n" ); document.write( "==> \"cos2x+cosx+-+2%28sinx%29%5E2%2A+cosx++%2B+cosx+=+0\"
\n" ); document.write( "==> \"cosx%28cos2x+-+2%28sinx%29%5E2++%2B+1%29+=+0\"
\n" ); document.write( "==> \"cosx%281+-+2%28sinx%29%5E2+-+2%28sinx%29%5E2+%2B+1%29+=+0\"
\n" ); document.write( "==> \"cosx%282+-+4%28sinx%29%5E2%29+=+0\"
\n" ); document.write( "==> \"cosx%281-2%28sinx%29%5E2%29+=+0\"
\n" ); document.write( "==> cosx = 0 ==> x = \"pi%2F2\", \"%283pi%29%2F2\";
\n" ); document.write( "==> Also, \"%28sinx%29%5E2+=+1%2F2\", or \"sinx+=+sqrt%282%29%2F2\", \"sinx+=+-sqrt%282%29%2F2\"
\n" ); document.write( "==> x = \"pi%2F4\", \"%283pi%29%2F4\", \"%285pi%29%2F4\", \"%287pi%29%2F4\".\r
\n" ); document.write( "\n" ); document.write( "==> Solution set is { \"pi%2F2\", \"%283pi%29%2F2\", \"pi%2F4\", \"%283pi%29%2F4\", \"%285pi%29%2F4\", \"%287pi%29%2F4\" }.
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