document.write( "Question 434897: x^2+y^2-9=0 list the domain, range, center, and radius \n" ); document.write( "

Algebra.Com's Answer #302181 by lwsshak3(11628) $\"\"$ $\"About$

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x^2+y^2-9=0 list the domain, range, center, and radius
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\n" ); document.write( "\n" ); document.write( "Standard form for a circle: (x-h)^2+(y-k)^2=r^2, with (h,k) being the (x,y) coordinates of the center and r=radius.
\n" ); document.write( "x^2+y^2-9=0
\n" ); document.write( "x^2+y^2=9
\n" ); document.write( "As you can see, this is a standard form of the circle. Since you don't see (h,k), the coordinates of center are (0,0). Radius square is given as 9, so the radius is the sqrt(9)=3
\n" ); document.write( "Center: (0,0)
\n" ); document.write( "Radius: 3
\n" ); document.write( "Domain:[-3,3]
\n" ); document.write( "Range:[-3,3]
\n" ); document.write( "See graph of circle below:
\n" ); document.write( "..
\n" ); document.write( "y=+-(9-x^2)^.5
\n" ); document.write( " $\"+graph%28+300%2C+300%2C+-5%2C+5%2C+-5%2C+5%2C+%289-x%5E2%29%5E.5%2C-%289-x%5E2%29%5E.5%29+\"$ \n" ); document.write( "

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