document.write( "Question 436798: A canoeist paddled 6 miles upstream in 6 hours and returned to his starting point downstream in 45 minutes. What was the speed of the current? \n" ); document.write( "
Algebra.Com's Answer #302158 by mananth(16946)\"\" \"About 
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A canoeist paddled 6 miles upstream in 6 hours and returned to his starting point downstream in 45 minutes. What was the speed of the current?\r
\n" ); document.write( "\n" ); document.write( "distance = same both ways\r
\n" ); document.write( "\n" ); document.write( "let speed of canoe be x mph
\n" ); document.write( "current speed = y mph
\n" ); document.write( "..
\n" ); document.write( "speed = distance/time
\n" ); document.write( "against current x-y = 6/6
\n" ); document.write( "with current x+y = 6/(3/4)===>6*4/3===>8\r
\n" ); document.write( "\n" ); document.write( "x-y =1
\n" ); document.write( "x+y=8\r
\n" ); document.write( "\n" ); document.write( "Add the two equations
\n" ); document.write( "2x=9
\n" ); document.write( "x= 4.5 mph speed of boat
\n" ); document.write( "speed of current = 8-4.5 = 3.5 mph
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