document.write( "Question 436792: The teacher gave us problems based on the properties of logarithms. I understand some but still need a help with a few.the problem \"+log+%28+6%2C+a%5E2%2B2+%29+%2B+log+%28+6%2C+2+%29+=+2+\" and finally the harder one for me is \"+log+%28+5%2C+64+%29+-+log+%28+5%2C+8%2F3+%29+%2B+log+%28+5%2C+2+%29+=+log+%28+5%2C+4p+%29+\" \n" ); document.write( "
Algebra.Com's Answer #302146 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Just remember that logs are exponents or powers.
\n" ); document.write( "When you add them you achieve multiplication.
\n" ); document.write( "When you subtract them you achieve division.
\n" ); document.write( "When you multiply them you are multiplying over and over again.
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\n" ); document.write( "\n" ); document.write( "The teacher gave us problems based on the properties of logarithms. I understand some but still need a help with a few.the problem
\n" ); document.write( "log ( 6, a^2+2 ) + log ( 6, 2 ) = 2
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\n" ); document.write( "log6(a^2+2) + log6(2) = 2
\n" ); document.write( "---
\n" ); document.write( "log6[2a^2+4] = 2
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\n" ); document.write( "2a^2+4 = 6^2
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\n" ); document.write( "2a^2+4-36 = 0
\n" ); document.write( "2a^2-32 = 0
\n" ); document.write( "2(a^2-16) = 0
\n" ); document.write( "a^2-16 = 0
\n" ); document.write( "a = +/-4
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\n" ); document.write( "\n" ); document.write( "and finally the harder one for me is
\n" ); document.write( "log ( 5, 64 ) - log ( 5, 8/3 ) + log ( 5, 2 ) = log ( 5, 4p )
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\n" ); document.write( "log5(64) - log5(8/3) + log5(2) = log5(4p)
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\n" ); document.write( "log5[64*2/(8/3)] = log5(4p)
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\n" ); document.write( "log5[16/3] = log4(4p)
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\n" ); document.write( "4p = 16/3
\n" ); document.write( "p = 4/3
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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