document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=436698>Question 436698</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2x-3y=6<BR>\n" );
document.write( "4x+y=1 \r<BR>\n" );
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document.write( "the question is solve the system of equations i believe this is where i can do elimination or substitution but im kind of confused\r<BR>\n" );
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document.write( "thank you in advance </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #302119 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=302119\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> multiplying the 2nd equation by 3, and then adding it to the 1st equation ELIMINATES the y variable\r<BR>\n" );
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document.write( "(12x + 3y) + (2x - 3y) = 3 + 6 ___ 14x = 9 ___ x = 9/14\r<BR>\n" );
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document.write( "solving for y in the second equation, and then SUBSTITUTING the equivalent value of y into the first equation\r<BR>\n" );
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document.write( "y = 1 - 4x ___ 2x - 3(1 - 4x) = 6 ___ 2x - 3 + 12x = 6 ___ 14x = 9 ___ x = 9/14\r<BR>\n" );
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document.write( "both of these techniques finish by substituting the value of x into one of the equations to find the value of y </SPAN>\n" );
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