document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=436722>Question 436722</A>: <I><SPAN STYLE=\"word-break: break-all;\"> trying to factor 2x^3+7x^2-3x-18 completely given that x+2 is a factor.  Tried to factor the first 3 numbers and the last three but getting stuck and don't understand how x+2 fits in.  Help! (and thanks!) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #302107 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=302107\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> using either long or synthetic division, dividing 2x^3+7x^2-3x-18 by x+2 gives ___ 2x^2 + 3x - 9\r<BR>\n" );
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document.write( "2x^2 + 3x - 9 factors to ___ (2x - 3)(x + 3)\r<BR>\n" );
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document.write( "so the factors of 2x^3+7x^2-3x-18 are ___ (x + 2)(2x - 3)(x + 3) </SPAN>\n" );
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