document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=945>Question 945</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A daughter is 28 years younger than her father. in five years, the father will be 3 times as old as his daughter. How old is each now? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #302 by </B><A HREF=/tutors/aboutme.mpl?userid=usyim88hk><B>usyim88hk(158)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=usyim88hk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=302\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1)let the age of the daughter be x<BR>\n" );
document.write( "2)x + 28 is the age of her dad<BR>\n" );
document.write( "3)so x+5 will be the age of the daughter after 5 years<BR>\n" );
document.write( "4)and 3(x+5) will be the age of the dad after three years which is also equal   to 3x+15<BR>\n" );
document.write( "5)x+33 is also the age of her dad after five years<BR>\n" );
document.write( "6)so x+33 = 3x+15 (both the age of her father after 5 years)<BR>\n" );
document.write( "7)x+33-15=3x+15-15<BR>\n" );
document.write( "8)x+18=3x<BR>\n" );
document.write( "9)x+18-x=3x-x<BR>\n" );
document.write( "10)18=2x<BR>\n" );
document.write( "11)x=9(So the age of the girl now is 9 years old)<BR>\n" );
document.write( "12)the age of her father is x+28 so he is 37 years old now<BR>\n" );
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document.write( "Answer: age of the daughter is 9 and age of the dad is 37 </SPAN>\n" );
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