document.write( "Question 45456This question is from textbook intermediate algebra
\n" ); document.write( ": I am having trouble with this could someone explain and show me how to work this problem.\r
\n" ); document.write( "\n" ); document.write( "Preform the operations. Write the ansers without negative exponents. Assume that all varibles represent postive numbers.\r
\n" ); document.write( "\n" ); document.write( "(27x^-3)^-1/3 \n" ); document.write( "
Algebra.Com's Answer #30198 by AnlytcPhil(1806)\"\" \"About 
You can put this solution on YOUR website!
: I am having trouble with this could someone explain\r\n" );
document.write( "and show me how to work this problem. Perform the \r\n" );
document.write( "operations. Write the ansers without negative\r\n" );
document.write( "exponents. Assume that all varibles represent \r\n" );
document.write( "postive numbers. \r\n" );
document.write( "(27x^-3)^-1/3\r\n" );
document.write( "\r\n" );
document.write( "(27x-3)-1/3\r\n" );
document.write( "\r\n" );
document.write( "Give the 27 a 1 exponent\r\n" );
document.write( "\r\n" );
document.write( "(271x-3)-1/3\r\n" );
document.write( "\r\n" );
document.write( "Multiply the outer exponent -1/3 by each of the \r\n" );
document.write( "inner exponents:\r\n" );
document.write( "\r\n" );
document.write( "271·-1/3x-3·-1/3\r\n" );
document.write( "\r\n" );
document.write( "27-1/3x1\r\n" );
document.write( "\r\n" );
document.write( "To get rid of the negative exponent, put the \r\n" );
document.write( "whole thing over 1,\r\n" );
document.write( "\r\n" );
document.write( " 27-1/3x1\r\n" );
document.write( "---------\r\n" );
document.write( "   1\r\n" );
document.write( "\r\n" );
document.write( "then move the base and exponent from numerator \r\n" );
document.write( "to denominator, and change the sign of \r\n" );
document.write( "the exponent to positive:\r\n" );
document.write( "\r\n" );
document.write( "   x1\r\n" );
document.write( "---------\r\n" );
document.write( " 1·271/3\r\n" );
document.write( "\r\n" );
document.write( "Erase the 1 exponent in the numerator and the\r\n" );
document.write( "1 multiplier in the denominator:\r\n" );
document.write( "\r\n" );
document.write( "   x\r\n" );
document.write( "-------\r\n" );
document.write( " 271/3\r\n" );
document.write( "\r\n" );
document.write( "Now the 1/3 power is the same as the cube \r\n" );
document.write( "root, so now we have\r\n" );
document.write( "\r\n" );
document.write( "   x\r\n" );
document.write( "-------\r\n" );
document.write( " ³Ö27\r\n" );
document.write( "\r\n" );
document.write( "The cube root of 27 is 3, so the final \r\n" );
document.write( "answer is\r\n" );
document.write( "\r\n" );
document.write( "   x\r\n" );
document.write( "  ---\r\n" );
document.write( "   3\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );