document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=436406>Question 436406</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the number of years it would take to grow an initial investment of $2,000 to a future value of $5,000, at an interest rate of 8.5%, compounded annually.\r<BR>\n" );
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document.write( "formula: FVn=PV(1+i)n\r<BR>\n" );
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document.write( "FVn IS THE FUTURE VALUE OF THE INVESTMENT AFTER N YEARS<BR>\n" );
document.write( "PV IS THE INITIAL AMOUNT OF THE INVESTMENT<BR>\n" );
document.write( "i is the interest rate<BR>\n" );
document.write( "n is the length of the investment in years<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #301960 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=301960\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Amount=	5000							<BR>\n" );
document.write( "years=n								<BR>\n" );
document.write( "compounded	1							<BR>\n" );
document.write( "Rate =	8.5							<BR>\n" );
document.write( "Amount =	P*((n+r)/n)^n							<BR>\n" );
document.write( "								<BR>\n" );
document.write( "5000	=	2000	*(	1	+	0.09	)^	n<BR>\n" );
document.write( "2.5	=	*(	1	+	0.09	)^	n	<BR>\n" );
document.write( "ln	2.5	=	n	ln	1.09			<BR>\n" );
document.write( "	0.92	=	n	0.08				<BR>\n" );
document.write( "	11.23	=	n					<BR>\n" );
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