document.write( "Question 45455This question is from textbook intermediate algebra
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document.write( ": Sove the logarithmic equation, could you explain to me how to do this?\r
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document.write( "log x + log (x+9) = 1 \n" );
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Algebra.Com's Answer #30195 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! log x + log (x+9) = 1\r \n" ); document.write( "\n" ); document.write( "You have a log rule which says log a + log b = log ab\r \n" ); document.write( "\n" ); document.write( "So, you write:\r \n" ); document.write( "\n" ); document.write( " log x(x+9) =1\r \n" ); document.write( "\n" ); document.write( "You know a transformation which says \r \n" ); document.write( "\n" ); document.write( "log b = c means the same as b=10^c\r \n" ); document.write( "\n" ); document.write( "So you write: \n" ); document.write( "x(x+9)=10^1 \n" ); document.write( "x^2+9x-10=0 \n" ); document.write( "(x+10)(x-1)=0\r \n" ); document.write( "\n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "x=-10 or x=1\r \n" ); document.write( "\n" ); document.write( "You check these answers in the original equation \n" ); document.write( "and see that x=-10 cannot be a solution because you \n" ); document.write( "cannot have the log of a negative number.\r \n" ); document.write( "\n" ); document.write( "So, x=1 is the only solution of your original equation.\r \n" ); document.write( "\n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |