document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=436402>Question 436402</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could someone please check my work and show me how to finish this problem? solve by substitution<BR>\n" );
document.write( "7m+n=42, m-7n=56\r<BR>\n" );
document.write( "\n" );
document.write( "7m+n=42<BR>\n" );
document.write( "7m=42-n<BR>\n" );
document.write( "m=(42n)/7<BR>\n" );
document.write( "m-7n=56<BR>\n" );
document.write( "42-n-49=392 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #301945 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=301945\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> m-7n=56  m=7n+56<BR>\n" );
document.write( "7m+n=42<BR>\n" );
document.write( "7(7n+56)+n=42<BR>\n" );
document.write( "49n+392+n=42<BR>\n" );
document.write( "50n=-350<BR>\n" );
document.write( "n=-7<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "7m-7=42<BR>\n" );
document.write( "7m=49<BR>\n" );
document.write( "m=7<BR>\n" );
document.write( "----------------<BR>\n" );
document.write( "proof<BR>\n" );
document.write( "m-7n=56<BR>\n" );
document.write( "7-7*-7=56<BR>\n" );
document.write( "7+49=56 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );