document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=45456>Question 45456</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0534493947/algebrahomeworkh>intermediate algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> I am having trouble with this could someone explain and show me how to work this problem.\r<BR>\n" );
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document.write( "Preform the operations. Write the ansers without negative exponents. Assume that all varibles represent postive numbers.\r<BR>\n" );
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document.write( "(27x^-3)^-1/3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #30193 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=30193\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (27x^-3)^-1/3\r<BR>\n" );
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document.write( "The \"negative\" in the exponent means to invert.<BR>\n" );
document.write( "The \"1/3\" in the exponent means to take the cube root.\r<BR>\n" );
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document.write( "=(27)^(-1/3)*(x^-3)^(-1/3)\r<BR>\n" );
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document.write( "= (3)^-1 *(x^1)<BR>\n" );
document.write( "=(1/3) x\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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