document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=436378>Question 436378</A>: <I><SPAN STYLE=\"word-break: break-all;\"> raj says to shyam \"i was twice as old as you were when i was as old as you now. if the sum of their present ages is 50 years .find their present ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #301915 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=301915\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x equal raj's age,y equals shyam's.  The difference between their ages now is (x-y). When x was y's age, he was twice as old as y was then.  Now he is three times as old as y was then. So:<BR>\n" );
document.write( "x-y=(1/3)x<BR>\n" );
document.write( "3x-3y=x<BR>\n" );
document.write( "2x=3y<BR>\n" );
document.write( "x+y=50<BR>\n" );
document.write( "2x+2y=100<BR>\n" );
document.write( "3y+2y=100<BR>\n" );
document.write( "5y=100<BR>\n" );
document.write( "y=20<BR>\n" );
document.write( "x=30.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );