document.write( "Question 436249: Hi everyone, could you help me solve this equation?
\n" ); document.write( "Thank you so much,
\n" ); document.write( "Alexa\r
\n" ); document.write( "\n" ); document.write( "26. The area of a playground is 221 yd^2. The width of the playground is 4 yd longer than its length. Find the length and width of the playground.\r
\n" ); document.write( "\n" ); document.write( "(Hint: Include correct units in your final answer.) (3 points) \n" ); document.write( "
Algebra.Com's Answer #301908 by ankor@dixie-net.com(22740)\"\" \"About 
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26. The area of a playground is 221 yd^2. The width of the playground is 4 yd longer than its length.
\n" ); document.write( " Find the length and width of the playground.
\n" ); document.write( ":
\n" ); document.write( "L*W = 221
\n" ); document.write( "It says,\"The width of the playground is 4 yd longer than its length.\" therefore
\n" ); document.write( "W = (L+4)
\n" ); document.write( "so we can replace W:
\n" ); document.write( "L(L+4) = 221
\n" ); document.write( "L^2 + 4L = 221
\n" ); document.write( "L^2 + 4L - 221 = 0
\n" ); document.write( "You can solve this using the quadratic formula, but it will factor to:
\n" ); document.write( "(L+17)(L-13) = 0
\n" ); document.write( "the positive solution
\n" ); document.write( "L = 13 yds is the length
\n" ); document.write( "then
\n" ); document.write( "13 + 4 = 17 yds is the width
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check by finding the area with these dimensions:
\n" ); document.write( "13 * 17 = 221 sq/yds
\n" ); document.write( ":
\n" ); document.write( "Sorry about the wrong units here \n" ); document.write( "
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