document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=436339>Question 436339</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the equation of the line that passes through (-3.5) and perpendincular to a line 3x-6y-7 = 0 (p.s put this line in the form of y=mx+c)  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #301879 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=301879\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the equation of the line that passes through (-3.5) and perpendincular to a line 3x-6y-7 = 0 (p.s put this line in the form of y=mx+c) <BR>\n" );
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document.write( "If 3x-6y-7 = 0<BR>\n" );
document.write( "6y = 3x-7<BR>\n" );
document.write( "y = (1/2)x-(7/6)<BR>\n" );
document.write( "Slope = 1/2<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "Any line perpendicular to the given line must <BR>\n" );
document.write( "have slope = -2<BR>\n" );
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document.write( "Find equation of line thru (-3,5) with slope = -2.<BR>\n" );
document.write( "Form: y = mx+b<BR>\n" );
document.write( "5 = -2*-3+b<BR>\n" );
document.write( "b = -1<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "y = (1/2)x-1<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "================ </SPAN>\n" );
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