document.write( "Question 436290: I think I picked the right area for this [?].
\n" ); document.write( "I am at a loss to set this one up in formulas.
\n" ); document.write( "I get the rate/minute idea but get lost setting up an equation to get the answer.
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\n" ); document.write( "\n" ); document.write( "A fire engine starts pumping water at 9:20 am at the rate of 800 gallons per minute. Another fire engine, pumping at the rate of 1,000 gallons per minute, starts at 9:30 am. At what time will the 2 engines have pumped the same number of gallons? \r
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Algebra.Com's Answer #301829 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A fire engine starts pumping water at 9:20 am at the rate of 800 gallons per minute.
\n" ); document.write( " Another fire engine, pumping at the rate of 1,000 gallons per minute, starts at 9:30 am.
\n" ); document.write( " At what time will the 2 engines have pumped the same number of gallons?
\n" ); document.write( ":
\n" ); document.write( "Let m = no. of minutes first fire engine pumping time
\n" ); document.write( "then
\n" ); document.write( "(m-10) = pumping time of the 2nd fire engine, (started 10 min after the 1st engine)
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\n" ); document.write( "2nd engine gal = 1st engine gal
\n" ); document.write( "1000(m-10) = 800m
\n" ); document.write( "1000m - 10000 = 800m
\n" ); document.write( "1000m - 800m = 10000
\n" ); document.write( "200m = 10000
\n" ); document.write( "m = \"10000%2F200\"
\n" ); document.write( "m = 50 minutes after 1st engine starts pumping
\n" ); document.write( "therefore
\n" ); document.write( "9:20 + :50 = 10:10, they will have pumped the same
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\n" ); document.write( "Check this by finding the actual amt for each pump, they should be equal
\n" ); document.write( "50*800 = 40000
\n" ); document.write( "40*1000= 40000
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