document.write( "Question 436289: log(8x-1)=2\r
\n" ); document.write( "\n" ); document.write( "how would I solve this?
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Algebra.Com's Answer #301828 by Gogonati(855)\"\" \"About 
You can put this solution on YOUR website!
Assume logarithm to base 10 and rewrite the equation.\r
\n" ); document.write( "\n" ); document.write( "\"log%2810%2C+8x-1%29=log%2810%2C+100%29\", since the logarithms are equal we have;\r
\n" ); document.write( "\n" ); document.write( "\"8x-1=100\"\r
\n" ); document.write( "\n" ); document.write( "\"8x=101\"\r
\n" ); document.write( "\n" ); document.write( "\"x=101%2F8\".\r
\n" ); document.write( "\n" ); document.write( "Done.
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