document.write( "Question 436260: solve for x\r
\n" ); document.write( "\n" ); document.write( "log(base 10)X+log(base 10)(X+1) = log(base 10)12
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Algebra.Com's Answer #301823 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
log(base 10)X+log(base 10)(X+1) = log(base 10)12
\n" ); document.write( "log(base 10)X(X+1) = log(base 10)12
\n" ); document.write( "X(X+1) = 12
\n" ); document.write( "X^2+X = 12
\n" ); document.write( "X^2+X-12 = 0
\n" ); document.write( "(X+4)(X-3) = 0
\n" ); document.write( "X = {-4,3}
\n" ); document.write( "Throw out the negative solution (extraneous) leaving:
\n" ); document.write( "X = 3
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