document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=436178>Question 436178</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 12 m/sThe energy, E, released when an object is stopped varies directly as the square of its velocity, v. If an object releases 600kj of energy when stopped from a velocity of 5m/s. How much energy is released when it is stopped from a speed of 12m/s? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #301800 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=301800\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since the energy varies directly as the square of the velocity, we can write:<BR>\n" );
document.write( "E = kv^2<BR>\n" );
document.write( "where k is a constant<BR>\n" );
document.write( "Given: 600 kJ released when v = 5 m/s.  <BR>\n" );
document.write( "Use this information to find k:<BR>\n" );
document.write( "600 kJ = k(5 m/s)^2<BR>\n" );
document.write( "k = 600/25 = 24 kJ*s^2/m^2<BR>\n" );
document.write( "So, the energy released when v = 12 m/s is:<BR>\n" );
document.write( "E = 24(12)^2 = 3456 kJ </SPAN>\n" );
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