document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=436188>Question 436188</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the area of the largest square that can be cut out of a circular paper with a circumference of 20&#960; cm </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #301785 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=301785\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2*pi*r= 20*pi<BR>\n" );
document.write( "r=10<BR>\n" );
document.write( "the diagonal of the square will be twice the radius.<BR>\n" );
document.write( "diagonal = 20<BR>\n" );
document.write( "The diagonal is the hypotenuse of traiangle with the legs as the sides of the square<BR>\n" );
document.write( "20^2=2x^2<BR>\n" );
document.write( "400=2x^2<BR>\n" );
document.write( "200=x^2<BR>\n" );
document.write( "x= sqrt(200)\r<BR>\n" );
document.write( "\n" );
document.write( "Area will be sqrt(200)*sqrt(200)<BR>\n" );
document.write( "= 200 sq. cm<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );