document.write( "Question 436052: HELP, PLZ.....
\n" ); document.write( "A woman commutes to work first by train, then rides a bicycle from the station to her office. The train averages 50 mi/h, and she averages 15 mi/h on her bicycle. The total distance of her commute is 13 miles, and the combined trip takes 24 minutes. How far does she ride the train?
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Algebra.Com's Answer #301706 by ankor@dixie-net.com(22740)\"\" \"About 
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A woman commutes to work first by train, then rides a bicycle from the station to her office.
\n" ); document.write( " The train averages 50 mi/h, and she averages 15 mi/h on her bicycle.
\n" ); document.write( " The total distance of her commute is 13 miles, and the combined trip takes 24 minutes.
\n" ); document.write( "How far does she ride the train?
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\n" ); document.write( "Let d = distance rode on the train
\n" ); document.write( "then
\n" ); document.write( "(13-d) = distance rode on the bike
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\n" ); document.write( "Convert 24 min: 24/60 = .4 hrs
\n" ); document.write( ":
\n" ); document.write( "Write a time equation: Time = dist/speed
\n" ); document.write( ":
\n" ); document.write( "Train time + bike time = total time
\n" ); document.write( "\"d%2F50\" + \"%28%2813-d%29%29%2F15\" = .4 hrs
\n" ); document.write( "Multiply by 150
\n" ); document.write( "150*\"d%2F50\" + 150*\"%28%2813-d%29%29%2F15\" = 150(.4)
\n" ); document.write( "cancel the denominators
\n" ); document.write( "3d + 10(13-d) = 60
\n" ); document.write( "3d + 130 - 10d = 60
\n" ); document.write( "3d - 10d = 60 - 130
\n" ); document.write( "-7d = -70
\n" ); document.write( "d = +10 miles on the train
\n" ); document.write( ":
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\n" ); document.write( "Check by finding time of each
\n" ); document.write( "10/50 = .2 hr
\n" ); document.write( "3/15 = .2 hrs
\n" ); document.write( "--------------
\n" ); document.write( "total .4 hrs which is 24 min
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