document.write( "Question 436052: HELP, PLZ.....
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document.write( "A woman commutes to work first by train, then rides a bicycle from the station to her office. The train averages 50 mi/h, and she averages 15 mi/h on her bicycle. The total distance of her commute is 13 miles, and the combined trip takes 24 minutes. How far does she ride the train? \n" );
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Algebra.Com's Answer #301706 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A woman commutes to work first by train, then rides a bicycle from the station to her office. \n" ); document.write( " The train averages 50 mi/h, and she averages 15 mi/h on her bicycle. \n" ); document.write( " The total distance of her commute is 13 miles, and the combined trip takes 24 minutes. \n" ); document.write( "How far does she ride the train? \n" ); document.write( ": \n" ); document.write( "Let d = distance rode on the train \n" ); document.write( "then \n" ); document.write( "(13-d) = distance rode on the bike \n" ); document.write( ": \n" ); document.write( "Convert 24 min: 24/60 = .4 hrs \n" ); document.write( ": \n" ); document.write( "Write a time equation: Time = dist/speed \n" ); document.write( ": \n" ); document.write( "Train time + bike time = total time \n" ); document.write( " \n" ); document.write( "Multiply by 150 \n" ); document.write( "150* \n" ); document.write( "cancel the denominators \n" ); document.write( "3d + 10(13-d) = 60 \n" ); document.write( "3d + 130 - 10d = 60 \n" ); document.write( "3d - 10d = 60 - 130 \n" ); document.write( "-7d = -70 \n" ); document.write( "d = +10 miles on the train \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check by finding time of each \n" ); document.write( "10/50 = .2 hr \n" ); document.write( "3/15 = .2 hrs \n" ); document.write( "-------------- \n" ); document.write( "total .4 hrs which is 24 min \n" ); document.write( " |