document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=436015>Question 436015</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A girl drove 4 hours there and drove back in 3 hours. What were her speeds if her speed coming back was 11 mph greater than her speed there? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #301696 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=301696\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the girl's speed.  Her distance traveled is 4x.  The same distance traveled back was at x+11 for 3 hours. Therefore:<BR>\n" );
document.write( "4x=3(x+11)<BR>\n" );
document.write( "4x=3x+33<BR>\n" );
document.write( "x=33<BR>\n" );
document.write( "Her speed there was 33mph.  Her speed back was 44 miles per hour. </SPAN>\n" );
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