document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=436044>Question 436044</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many gallons of a solution of 20% acid must be blended with a solution of 5% acid to obtain 80 gallons of a solution of 12% acid<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #301687 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=301687\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 80 gallons of 12% acid equals 9.6 gallons of pure acid.<BR>\n" );
document.write( "x+y=80<BR>\n" );
document.write( ".20x+.05y=9.6<BR>\n" );
document.write( "Multiply the second equation by 100:<BR>\n" );
document.write( "20x+5y=960<BR>\n" );
document.write( "x+y=80<BR>\n" );
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document.write( "20x+5y=960<BR>\n" );
document.write( "5x+5y=400<BR>\n" );
document.write( "15x=560<BR>\n" );
document.write( "x=37 1/3<BR>\n" );
document.write( "y=42 2/3. </SPAN>\n" );
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