document.write( "Question 436044: How many gallons of a solution of 20% acid must be blended with a solution of 5% acid to obtain 80 gallons of a solution of 12% acid
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Algebra.Com's Answer #301685 by mananth(16946)![]() ![]() You can put this solution on YOUR website! percent ---------------- quantity \n" ); document.write( "Acid I 20 ---------------- x gallons \n" ); document.write( "Acid II 5 ---------------- 80 - x gallons \n" ); document.write( "Total 12.00% ---------------- 80 \n" ); document.write( " \n" ); document.write( "20x+5(80-x)=12*80 \n" ); document.write( "20x+400-5x=960 \n" ); document.write( "20x-5x=960-400 \n" ); document.write( "15x=560 \n" ); document.write( "/15 \n" ); document.write( "x=37.33 gallons 20.00% \n" ); document.write( "42.67 gallons 5.00% \n" ); document.write( " |