document.write( "Question 435976: a man invested 10000$,part at 5 percent and part at 9 percent.if the total yearly interest was 600$, how much did he invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #301684 by jorel1380(3719)\"\" \"About 
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x+y=10000
\n" ); document.write( ".05x+.09y=600
\n" ); document.write( "Multiply the second equation by 100
\n" ); document.write( "5x+9y=60000
\n" ); document.write( "5x+5y=50000
\n" ); document.write( "----------
\n" ); document.write( "4y=10000
\n" ); document.write( "y=2500
\n" ); document.write( "x=7500
\n" ); document.write( "He invested $7500 at 5% and $2500 at 9%.
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