document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=435452>Question 435452</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve for x:  ln(2x+3)+ln(x)=ln(e) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #301659 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=301659\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do you solve for x: ln(2x+3)+ln(x)=ln(e)<BR>\n" );
document.write( "..<BR>\n" );
document.write( "ln(2x+3)+ln(x)=ln(e)<BR>\n" );
document.write( "ln(2x+3)(x)=1<BR>\n" );
document.write( "convert to exponential form<BR>\n" );
document.write( "e^1=2x^2+3x<BR>\n" );
document.write( "2x^2+3x-e=0<BR>\n" );
document.write( "solve by quadratic formula<BR>\n" );
document.write( "a=2, b=3, c=-e<BR>\n" );
document.write( "x=(-3+-Sqrt(3^2-4*2*-e))/2*2<BR>\n" );
document.write( "x=(-3+-sqrt(30.75))/4<BR>\n" );
document.write( "x=(-3+-5.55)=-8.55/4 or 2.55/4=-2.14 or .64<BR>\n" );
document.write( "x=-2.14 (reject, (2x+3)>0)<BR>\n" );
document.write( "x=.64 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );