document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=435857>Question 435857</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Barbara invested $100 at a certain rate of interest compounded anually for two years.  If the accumulated value at the end of two years is $121, find the rate of interest. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #301630 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=301630\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The interest formula can be written:<BR>\n" );
document.write( "P = Po(1+r)^n<BR>\n" );
document.write( "In this case n=2, Po=100, P=121<BR>\n" );
document.write( "Put in the numbers and solve for r:<BR>\n" );
document.write( "121 = 100(1+r)^2<BR>\n" );
document.write( "sqrt(121/100) = 1+r -> r = 0.1<BR>\n" );
document.write( "Therefore the interest rate was 10% </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );