document.write( "Question 435783: This is calculus - limits\r
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Algebra.Com's Answer #301625 by richard1234(7193) $\"\"$ $\"About$

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$\"lim%28x-%3Einfinity%2C+x%5E2e%5E%28-x%29%29+=+lim%28x-%3Einfinity%2C+x%5E2%2Fe%5Ex%29\"$ . This is indeterminate so we use L'Hopital's rule:\r
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. This limit is equal to zero, so the limit of the original expression is also equal to zero. \n" ); document.write( "

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