document.write( "Question 435794: 8x^(2)+7x-1=0
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Algebra.Com's Answer #301600 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "8x^(2)+7x-1=0
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document.write( "factoring
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document.write( "(8x-1)(x+1)= 0   Note:SUM of the outside terms(8x) and the inside terms(-x) = 7x
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document.write( "(8x-1)= 0   x = 1/8
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document.write( " (x+1)= 0   x = -1 \n" );
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