document.write( "Question 435808: find an equation in standard form of the line containing the given points: (1/6,-1/3) (5/6,3) \n" ); document.write( "
Algebra.Com's Answer #301594 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "Using the point-slope formula, \"m+=%28y%5B2%5D+-+y%5B1%5D%29%2F%28x%5B2%5D+-+x%5B1%5D%29\"
\n" ); document.write( "(1/6,-1/3)
\n" ); document.write( "(5/6, 3) m = \"%28-4%2F3%29%2F%28-4%2F6%29+=+2\"
\n" ); document.write( "Using the standard slope-intercept form for an equation of a line y = mx + b
\n" ); document.write( " where m is the slope and b the y-intercept.
\n" ); document.write( " y = 2x+ b
\n" ); document.write( " 3 = 2*5/6 + b |using ordered pair Pt(5/6,3) to solve for b
\n" ); document.write( " 1/3 = b
\n" ); document.write( " y = 2x + 1/3 OR 6x - 3y = -1
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