document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=435792>Question 435792</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A person buys 20 tickets. some cost $8 and some cost $5. he spend $118. <BR>\n" );
document.write( "How many of each ticket does he buy? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #301591 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=301591\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the number of $5 tickets <BR>\n" );
document.write( "Then 20-x = the number of $8 tickets<BR>\n" );
document.write( "Since the total amount spent is $118, we can write:<BR>\n" );
document.write( "5x + 8(20-x) = 118<BR>\n" );
document.write( "Collect terms, solve for x:<BR>\n" );
document.write( "-3x + 160 = 118 -> 3x = 42 -> x = 14<BR>\n" );
document.write( "So the number of $5 tickets is 14, the number of $8 tickets is 6. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );